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my friend has 2 cards for access control system Siemens.
Its a conventional 64-bit card.
but the code is printed on the cards somehow encrypted.
I have not been able to understand exactly how.
Maybe some one knows?
0F00CD7CF1 => 0011000653 (printed)
0F00CD9C42 => 0010969444 (printed)
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In my very humble opinion the decimal value, converted in binary, is obtained taking specific bits of the hex value converted in bin; in practice there is a bit scrambling only, no encryption. I think I will be able to identify a correlation if I have 2 more examples, for now I seem to have located 8 bits only.
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I've seen this. I believe it to be just as asper said.. Pattern goes like this: convert hex ID to binary:
bit 18,20,17,19,23,21,24,22,26,28,25,27,35,37,40,34,31,29,39,38,36,30,32,33
no 0 bit in count, count from left(msb). (Make sure to pad leading zeros.)
Convert binary to decimal.
You said this is for a Siemens? Do you know the reader/models?
Last edited by marshmellow (2014-10-06 05:37:06)
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Wow! You were able to detect the scrambling pattern with 2 IDs only! Can you explain me how you did it?
@sentinel: what is the name of the system?
Last edited by asper (2014-10-06 06:01:10)
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As I mentioned, I've seen these tags before.
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I Just don't know the system they were used for
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As I mentioned, I've seen these tags before.
Missed it, sorry
Last edited by asper (2014-10-06 14:44:58)
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actually you've seen this format before as well asper.. it is already included in the [EM4100-Unique blocks calculator.xlsm], you made (or helped make?)...
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You are right, I assumed it was a new format without checking the calculator... I would have saved time...
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The speed of solving the problem is fantastic)) thank you very much, Мarshmellow
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